prove e xy e x e y

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prove e xy e x e y The proof in the discrete case is analogous This shows why independence of X X and Y Y implies that E XY E X E Y E X Y E X E Y The converse does not necessarily

Basically E XY E E XY Y E YE X Y E X Y E E X Y Y E Y E X Y The first step is the iterated rule of conditional expectation For the second use the fact that If X and Y are independent then E XY E X E Y However the converse is not generally true it is possible for E XY E X E Y even though X and Y are dependent

prove e xy e x e y

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prove e xy e x e y
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Solved E XY E X E Y If X And Y Are Independent Select Chegg
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Probability Question About Book Solution To Estimate E e XY When
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The conditional mean and variance have the following useful properties You can reduce this question to this why is E XY X XE Y X E X Y X X E Y X with probability 1 If this is true then you can just take expectations on both sides The

By the expression E XY E X Y we mean the expectation of XY under their joint distribution I e if these both are continuous we have that E XY xyf x y dxdy E X Y x y f x y d x d y where f x y f x y is the It is often much easier to use fX x than to first find fY y then find E Y Proof We prove the theorem for discrete r v s Consider E Y Xy

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Prove E XY E X E Y if X and Y are independent E XY E X E Y var X Y var X var Y

Let X Rk and Y Rk be random variables in some probability space F P and let R Then E X Y E X E Y Proof E X Y X Y dP XdP Cov X Y E XY E X E Y Thus Cov X E Y X E X E Y X E X E E Y X As such to solve the problem we need to show that E X E Y X E XY

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prove e xy e x e y - The same idea is used early in calculus in showing that if f x f x then f x is a constant times ex