y 3 5 x 2 y 1 5 x 4

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y 3 5 x 2 y 1 5 x 4 Solve an equation inequality or a system Example 2x 1 y 2y 3 x 1 2 3 4 5 6 7 8 9 0 F A x y G

Tap for more steps Slope 1 5 1 5 y intercept 0 4 0 4 x y 0 4 5 5 x y 0 4 5 5 Plot each graph on the same coordinate system y 3 5x 2 y 3 5 x 2 y 1 5x 4 y 1 5 x 4 High School Math Solutions Quadratic Equations Calculator Part 1 A quadratic equation is a second degree polynomial having the general form ax 2 bx c 0 where a b and c Enter a problem Cooking Calculators Cooking Measurement Converter Cooking Ingredient Converter Cake Pan Converter More calculators

y 3 5 x 2 y 1 5 x 4

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y 3 5 x 2 y 1 5 x 4
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Solved Sketch The Region Enclosed By The Given Curves Chegg
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Algebra Solve for y 3 1 5y 2x 4 3 1 5 y 2x 4 3 1 5 y 2 x 4 Combine 1 5 1 5 and y y 3 y 5 2x 4 3 y 5 2 x 4 Move all terms not containing y y to the right side of the equation Tap for more steps y 5 2x 1 y 5 2 x 1 Multiply both sides of the equation by 5 5 5y 5 5 2x 1 5 y 5 5 2 x 1 Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more

Explanation displaystyle 5 y 2 x 3 displaystyle y frac 2 5 x frac 3 5 solve for y in terms of x displaystyle 4 x 10 left frac 2 5 x frac 3 5 right 6 Step 4 Putting them together in latex y mx b latex form since latex m 3 latex and latex b 25 latex we have the slope intercept form of the line as Step 5 Using a graphing utility show that the solved linear equation in slope intercept form passes through the two points

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Given two points on a line we can write an equation for that line by finding the slope between those points then solving for the y intercept in the slope intercept equation y mx b In this example we write an equation of the line that passes through the points Sal graphs the following system of equations and solves it by looking for the intersection point y 7 5x 5 and y 3 5x 1 Created by Sal Khan

Combine the numerators together put the sum or difference over the common denominator then reduce to lowest terms if possible y 3 5 4 x 5y x 19 5 5 Equation at the end of step 3 5y x 19 Ex 3 3 1 Elimination Solve the following pair of linear equations by the elimination method and the substitution method i x y 5 and 2x 3y 4 x y 5 2x 3y 4 Multiplying equation 1 by 2 2 x y 2 5 2x 2y 10 Solving 3 and 2 by Elimination 5y 6 5y 6 y Putting y 6 5 in 1 x y 5

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y 3 5 x 2 y 1 5 x 4 - Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more