x 4 2x 3 7x 2 8x 12

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x 4 2x 3 7x 2 8x 12 Divide x 3 3x 2 4x 12 by x 2 to get x 2 x 6 Solve the equation where the result equals to 0 x frac left 1 right sqrt left 1 right 2 4 times 1 left 6 right 2

X4 2x3 7x2 8x 12 0 Four solutions were found x 3 x 2 x 1 x 2 Step by step solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 0 Step 2 Precalculus Find the Roots Zeros x 4 2x 3 7x 2 8x 12 x4 2x3 7x2 8x 12 Set x4 2x3 7x2 8x 12 equal to 0 x4 2x3 7x2 8x 12 0 Solve for x Tap for more

x 4 2x 3 7x 2 8x 12

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x 4 2x 3 7x 2 8x 12
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If X 2 2x 3 3x 4 2x 3 3x 4 4x 5 3x 5 5x 8 10x 17
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Solution Finding the roots of polynomials Step by Step Solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 Step 2 Equation at the end of step 2 Calculus matrices variables list Examples Quadratic equation x2 4x 5 0 Trigonometry 4sin cos 2sin Linear equation y 3x 4 Arithmetic 699 533

Step by step solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 0 Step 2 Equation at the end of step 2 x4 2x3 7x2 8x 12 0 Step by step solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 0 Step 2 Equation at the end of step 2 x4 2x3 7x2 8x

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Explanation Given P x x4 2x3 7x2 8x 12 Rational roots theorem The rational roots theorem tells us that the rational zeros of P x are expressible as p q Answer in Brief x 4 2x 3 7x 2 8x 12 Advertisements Solution Let f x x 4 2 x 3 7 x 2 8 x 12 be the given polynomial Now putting x 1 we get f 1 1 4

Solution Verified by Toppr Given equation x 4 2x 3 7x 2 8x 12 0 Consider f x x 4 2x 3 7x 2 8x 12 By inspection we can easily see that f 1 0 Therefore x 1 is one X4 2x3 7x2 8x 12 Final result x4 2x3 7x2 8x 12 Step by step solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 Step 2 Equation at the end

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x 4 2x 3 7x 2 8x 12 - Step by step solution Step 1 Equation at the end of step 1 x4 2 x3 7x2 8x 12 0 Step 2 Equation at the end of step 2 x4 2x3 7x2 8x