x 3 x 2 4x 2sinx 0

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x 3 x 2 4x 2sinx 0 X 3 x 2 2 2sinx 4 Clearly x 0 satisfies the equations If 0 x x 3 x 2 2 2sinx 4 If x 2 x 3 x 2 2 2sinx 27 25 2 So x 0 is the only solution

Mathematics Exponential Function a x Question The number of solutions of the equation x3 x2 4x 2sinx 0 in 0 x 2 is A zero B one C two D four Solution Verified by Toppr Was this answer helpful 1 Similar Questions Q 1 The number of solutions of the equation cot x cot x 1 sinx 0 x 2 is View Solution Q 2 X 2 sin x sin cos 1 cos 0 4 5 and Then n 0 n n 1 n is equal to

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A basic trigonometric equation has the form sin x a cos x a tan x a cot x a If 0 le x le 2pi then the number of real values of x which satisfy the equation cos x cos 2x cos 3x cos 4x 0 is

The number of solutions of the equation x 3 x 2 4x 2sinx 0 in 0 le x le 2pi is To solve a trig equation transform it into one or many basic trig equations Solving a trig equation finally results in solving various basic trig equations There are 4 main basic trig equations sin x a cos x a tan x a cot x a Exp Solve sin 2x 2sin x 0

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The correct Answer is B We have x 3 x 2 4 x 2 sin x 0 x 3 x 2 2 2 sin x 4 We observe that x 0 satisfies this equation Also x 3 x 2 2 2 sin x 4 for 0 x and x 3 x 2 2 2 sin x 27 for x 2 Thus x 0 is the only solution of the given equation Updated on 21 07 2023 Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more

Consolidate the answers Tap for more steps x n 3 for any integer n Free math problem solver answers your algebra geometry trigonometry calculus and statistics homework questions with step by step explanations just like a math tutor The number of roots of the equation x 3 x 2 2 x sin x 0 in 2 2 are

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x 3 x 2 4x 2sinx 0 - The number of solutions of the equation x 3 x 2 4x 2sinx 0 in 0 le x le 2pi is