limit of sin x as x approaches infinity

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limit of sin x as x approaches infinity What is the limit of sin x x as x goes to infinity Calculus Limits Limits at Infinity and Horizontal Asymptotes 3 Answers Trevor Ryan Sep 28 2015 By Squeeze Theorem this limit is 0 Explanation Since 0 0 sinx x 1 x x 1 and since lim 0 0 and lim 1 x 0 By Squeeze Theorem lim sinx x 0 Answer link

Limit of sin x sin x as x x tends to infinity Ask Question Asked 3 years 5 months ago Modified 3 years 5 months ago Viewed 3k times 2 I understand that 1 sin x 1 1 sin x 1 for any real x x However the function oscillates and doesn t approach a finite limit as x x tends to infinity The six basic trigonometric functions are periodic and do not approach a finite limit as x For example sinx oscillates between 1and 1 Figure The tangent function x has an infinite number of vertical asymptotes as x therefore it does not approach a finite limit nor does it approach as x

limit of sin x as x approaches infinity

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limit of sin x as x approaches infinity
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Limit Of X sin 1 x As X Approaches Infinity Calculus 1 Exercises
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Lim x 0sinx x and lim x 1 x2 1 x 1 each return the indeterminate form 0 0 when we blindly plug in x 0 and x 1 respectively However 0 0 is not a valid arithmetical expression It gives no indication that the respective limits are 1 and 2 Free limit calculator solve limits step by step

Since sin x is always somewhere in the range of 1 and 1 we can set g x equal to 1 x and h x equal to 1 x We know that the limit of both 1 x and 1 x as x approaches either positive or negative infinity is zero therefore the limit of sin x x as x approaches either positive or negative infinity is zero We say the limit as x x approaches of f x f x is 2 2 and write lim x f x 2 lim x f x 2 Similarly for x 0 x 0 as the values x x get larger the values of f x f x approaches 2 2 We say the limit as x x approaches of f x f x is 2 2 and write lim x f x 2 lim

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What is the limit of sin x as x approaches infinity Precalculus Graphing Rational Functions Limits End Behavior and Asymptotes 1 Answer AJ Speller Sep 30 2014 The sine function oscillates from 1 to 1 Because of this the limit does not converge on a single value So the lim x sin x DN E which means the limit Does Not Exist Find the limit of 2x x as x approaches infinity As I interpret the question as x approaches infinity the expression becomes 2 Since two times infinity is equal to infinity my answer will be which evaluates to 1 Why is my answer faulty Correct answer is

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limit of sin x as x approaches infinity - We say the limit as x x approaches of f x f x is 2 2 and write lim x f x 2 lim x f x 2 Similarly for x 0 x 0 as the values x x get larger the values of f x f x approaches 2 2 We say the limit as x x approaches of f x f x is 2 2 and write lim x f x 2 lim