integration of x n

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integration of x n First let s take any n 1 and integrate xnsinxdx by parts to see what happens By the LIATE Rule we should take u1 xn and dv1 sinxdx giving us du1 nxn 1dx and v1 cosx Then xnsinxdx u1dv1 u1v1 v1du1 xncosx n xn 1cosxdx The integral on the far right is easy when n 1 but if n 2 then

int 0 x x n ln x ndx which is very complete in regards to integration of trascendental In school we have just started with integration by parts We had examples like x sin x dx or x 2 sin x dx I asked myself if it is possible to integrate terms like x 25 sin x dx without doing integration by parts 25 times

integration of x n

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integration of x n
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The webpage provides a step by step guide on how to integrate the function int sin n x dx using various techniques The integration by parts does not give that If you have an indefinite integral it gives an indefinite integral If you have a definite integral then you need to evaluate the corresponding indefinite integral over the given interval Specifically xn ex dx xn ex nxn 1 ex dx and hence 0 xn ex dx xn ex 0

In summary the answer is not log x log x or log x C The answer is that F x 1 x on R implies that there are constants C1 C2 R such that F x log x C1 for all x 0 and F x log x C2 for all x 1 Answer Sorted by 1 Integration is not so straightforward as differentiation We can have continuous and even differentiable functions which have no analytic antiderivative This integral has no analytic solution except for a set of specific F x F x s F x xp F x x p for any p R p R is an example of a function where you

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I m wondering how to find out the definite integration of int y 0 x 1 x ndx I ve tried several integration techniques but couldn t make it Stack Exchange Network Stack Exchange network consists of 183 Q A communities including Stack Overflow the largest most trusted online community for developers to learn share their knowledge and build their careers

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integration of x n - The webpage provides a step by step guide on how to integrate the function int sin n x dx using various techniques