integral of exact form is zero

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integral of exact form is zero A form beta p is closed if d beta 0 A form beta p is exact if beta p d alpha p 1 for some form alpha p 1

I m trying to show that a 2 form on S 2 is exact if and only if it integrates to zero without appealing to de Rham s theorem basically only using the Poincar lemma that every closed Let f be a zero form on an open subset U R n and P a point in U with a choice of orientation We define the integral of f on P by P f f P In other words we just

integral of exact form is zero

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integral of exact form is zero
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Second the integral of an exact two form along a closed surface is zero this statement for surface integrals is analogous to the statement that the line integral of an exact one form along a closed curve vanishes Note that is closed but not exact and so can have a nonzero line integral over a closed curve As we saw in class the 1 form measures the angle a curve turns through the winding number

Let a and b be the end points of A and let t 3 2 3 v x t Z i x s ds aBy 3 2 2 v a x v b x 0 so v is in v t u Hence if we let be the form C1 0 U A we have and d u x t dx That is closed if d 0 and say that is exact if d for some k 1 form When k 0 the 0 form is also considered exact Note that Every exact form is closed since d d d2 0 A 0 form

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I 0 xi of the path which controls the amount of backtracking involved stays bounded In particular in the case when a b so that all paths are closed i e x0 xn we see that signed Prove that a 1 form phi on M is exact if and only if for every closed curve c int c phi 0 One way is an application of Stokes theorem if phi df then int c phi

In mathematics especially vector calculus and differential topology a closed form is a differential form whose exterior derivative is zero d 0 and an exact form is a differential form A differential 0 form zero form is defined to be a smooth function f on U the set of which is denoted C U If v is any vector in R n then f has a directional derivative v f which is

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integral of exact form is zero - D dx x y 0 the integration of which yields the implicit solution x y 0 If this equation can be solved for y in terms of x do so If the given differential equation is not in exact form