y x 4 6x 3 13x 2 10x 5 at 0 5 Y x4 6x3 13x2 10x 5 dy dx 4x3 18x2 26x 10 dy dx 0 5 10 Thus the slope of the tangent at 0 5 is 10 Ergo equation of the tangent is given as y 5
Solution Verified by Toppr We have y x4 6x3 13x2 10x 5 dy dx 4x3 18x2 26x 10 dy dx 1 3 4 18 26 10 2 Thus the slope of the tangent at 1 3 is 2 Find the equation of the tangent and the normal to the following curve at the indicated point y x 4 6x 3 13x 2 10x 5 at x 1 Find the equation of the tangent and the
y x 4 6x 3 13x 2 10x 5 at 0 5
y x 4 6x 3 13x 2 10x 5 at 0 5
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Find the equations of the tangent and normal to the given curves at the indicated points i y x4 6x3 13x2 10x 5 at 0 5 ii y x4 6x3 13x2 10x 5 at 1 3 iii v x3 at Y x 4 6x 3 13x 2 10x 5 On differentiaiing both sides w r t x we get Hence required equation of tangent is 2x y 2
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Find The Equations Of The Tangent And Normal To The Given Curves At The
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y x 4 6x 3 13x 2 10x 5 at 0 5 - Y x 4 6x 3 13x 2 10x 5 On differentiaiing both sides w r t x we get Hence required equation of tangent is 2x y 2