x 4 4x 3 ax 2 bx 1 0

x 4 4x 3 ax 2 bx 1 0 0 votes 3 4k views asked Jan 11 2020 in Mathematics by DevikaKumari 70 6k points closed Sep 11 2021 by DevikaKumari If the equation x4 4x3 ax2

Solution Verified by Toppr Let f x x4 4x3 ax2 bx 1 0 For a 6 b 4 f x x 1 4 Then 1 is positive root Was this answer helpful 0 Similar Questions Q 1 If x 4 4x 3 ax 2 bx 1 0 are positive real numbers Show that all the roots of the polynomial are equal My work I assume the contraposition that all the roots are not

x 4 4x 3 ax 2 bx 1 0

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x 4 4x 3 ax 2 bx 1 0
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The Following Figure Shows The Graph Of f x ax 2 bx c Then Find
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Solve Ax By C And Bx Ay 1 C Linear Equations Teachoo
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1 Answer Sorted by 4 It is useful to notice that your polynomial is a palyndromic polynomial If we set z x 1 x z x 1 x x4 ax3 bx2 ax 1 x2 View solution steps Graph Both Sides in 2D Graph in 2D Quiz Polynomial x4 x3 4x2 x 1 0 Similar Problems from Web Search If y x x1 then write the equation x4

Step 1 Enter the Equation you want to solve into the editor The equation calculator allows you to take a simple or complex equation and solve by best method possible Step 2 X 2 x 6 0 x 3 gt 2x 1 x 5 x 5 gt 0 10 1 x 10 4 sqrt 3 x 2 6 11x 6x 2 x 3 0 factor x 2 5x 6 simplify frac 2 3 frac 3 2 frac 1 4 x 2y 2x 5 x y 3

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Polynomial maximization If x4 ax3 3x2 bx 1 0 x 4 a x 3 3 x 2 b x 1 0 find the maximum value of a2 b2 a 2 b 2 Ask Question Asked 9 years Of the four roots is equal to their G M Hence are all equal and each equal to 1 E x 1 4 x4 4x3 6x2 4x 1Comparing a 6 b 4 Was this answer helpful 0

Maths Question If the equation x4 4x3 ax2 bx 1 0 has four positive roots then the value of a b is 4 2 6 cannot be determined A cannot be determined B 6 C 2 D 6 3 Solving x 2 4x 4 0 by the Quadratic Formula According to the Quadratic Formula x the solution for Ax 2 Bx C 0 where A B and C are numbers often called

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x 4 4x 3 ax 2 bx 1 0 - Step 1 Enter the Equation you want to solve into the editor The equation calculator allows you to take a simple or complex equation and solve by best method possible Step 2