x 4 25x 2 144 0

x 4 25x 2 144 0 Solve for x View solution steps All equations of the form ax 2 bx c 0 can be solved using the quadratic formula frac b sqrt b 2 4ac 2a Substitute 1 for a 25 for b and 144 for c

Algebra Solve by Factoring x 4 25x 2 144 0 x4 25x2 144 0 x 4 25 x 2 144 0 Rewrite x4 x 4 as x2 2 x 2 2 x2 2 25x2 144 0 x 2 2 25 x 2 144 0 Let u x2 u Free Pre Algebra Algebra Trigonometry Calculus Geometry Statistics and Chemistry calculators step by step

x 4 25x 2 144 0

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x 4 25x 2 144 0
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Solution steps x4 25x2 144 0 Rewrite the equation with u x2 and u2 x4 u2 25u 144 0 Solve u2 25u 144 0 u 16 u 9 u 16 u 9 Substitute back u x2 solve for x Solve x2 Solving x 4 25x 2 144 0 directly Earlier we factored this polynomial by splitting the middle term let us now solve the equation by Completing The Square and by using the Quadratic

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Factor the expression x 4 25x 2 144 We can factor the polynomial x 4 25x 2 144 using the rational root theorem which guarantees that for a polynomial of the form a nx n a n 1 x n X4 24x2 144 0 Two solutions were found x 2 3 3 4641 Step by step solution Step 1 Equation at the end of step 1 x4 23 3x2 144 0 Step 2 Trying to

To solve the equation x 4 25x 2 144 0 we can use a substitution method Let y x 2 This transforms the equation into a quadratic form y 2 25y 144 0 We can then Step 1 Equation at the end of step 1 x4 52x2 144 0 Step 2 Trying to factor by splitting the middle term 2 1 Factoring x4 25x2 144 The first term is x4 its coefficient is 1

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