x 4 2 X 2 8x 16 each term in the second bracket must be multiplied by each term in the first bracket rArr x 4 2 x 4 x 4 rArr color red x 4 x 4 color red x x
Standard form simply refers to the format of a mathematical expression where the terms are arranged by decreasing order of degree Where the degree is determined by the exponent value of the variable of each term For quadratic equations the standard form is ax 2 bx c Where ax 2 has a degree of 2 bx has a degree of 1 and c has a 1 Answer y x 4 2 Find some points on the graph to do the plot Complete the remaining part of the graph by symmetry y x 4 2 Find some points on the graph to do the plot x 0 y 16 x 1 y 9 x 2 y 4 x 3 y 1 x 4 y 0 Complete the
x 4 2
x 4 2
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Divide x 4 2 X 3 2 X 2 X 4 By X 2 X 1
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Remember that the limit definition of the derivative goes like this f x lim h 0 f x h f x h So for the posted function we have f x lim h 0 m x h b mx b h By multiplying out the numerator lim h 0 mx mh b mx b h By cancelling out mx s and b s lim h 0 mh h By cancellng out h s Using synthetic division diamond 5x 2 17x 15 div x 4 We have p x 5x 2 17x 15 and divisor x 4 We take coefficients of p x to 5 17 15
X 2 8x 16 A parabola in color blue standard form is color white x ax 2 bx c a 0 expand x 4 2 using FOIL x 2 4x 4x 16 x 2 8x 16larrcolor red in Int x 4 2 d x 1 3 x 4 3 C int x 4 2 d x Substitute u x 4 d u d x int x 4 2 d x int u 2 d u int u 2 d u 1 3 u 3 int x 4 2 d x 1 3 u 3 Undo substitution
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What is Factoring Completely For factoring polynomials factoring or factoring completely is always done using some set of numbers as possible coefficient We say we are factoring over the set x 3 x 2 5x 5 can be factored over the integers as x 1 x 2 5 x 2 5 cannot be factored using integer coefficients Explanation Considering f x y to find the inverse function the x and y values are switched giving the new equation of x y 4 2 Then solve for y x y 4 y x 4 Answer link The inverse of this function is f x sqrtx 4 Considering f x y to find the inverse function the x and y values are switched giving the new
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x 4 2 - Int x 4 2 d x 1 3 x 4 3 C int x 4 2 d x Substitute u x 4 d u d x int x 4 2 d x int u 2 d u int u 2 d u 1 3 u 3 int x 4 2 d x 1 3 u 3 Undo substitution