x 2 y 2 1 3 x 2y 3 answer

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x 2 y 2 1 3 x 2y 3 answer

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Obviously the partial derivatives exist at x y not 0 0 as it s a rational function and the denominator is never zero Now to find the partial derivatives at 0 0 you have lim x to 0 frac f x 0 f 0 0 x lim x to 0 frac frac x 2 0 2 x 2 y 2 Find an equation for a tangent line to the curve x 2 y 2 5 that passes through the point 1 1

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