minimum value of x 2 y 2 z 2 when ax by cz p is Let F x 2 y 2 z 2 ax by cz We form the equations F x 0 F y 0 F z 0 i e 2x a 0 2y b 0 2z c 0
Consider the sphere x2 y2 z2 r2 and the plane ax by cz d 0 Clearly we have to find the minimum radius of sphere so that it atleast touches the Complete step by step answer We have to find the minimum value of x2 y2 z2 x 2 y 2 z 2 when the given condition is ax by cz p a x b y c z p We
minimum value of x 2 y 2 z 2 when ax by cz p is
minimum value of x 2 y 2 z 2 when ax by cz p is
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Find the maximum and minimum values of x 2 y 2 z 2 subject to the condition ax 2 by 2 cz 2 1 and lz my ny 0 and interpret the result If ax by cz 1 what is the minimum of x 2 y 2 z 2 It is obvious that we can do Lagrangian multiplier W x 2 y 2 z 2 lambda ax by cz 1
Find the minimum value of x y z subject to the condition ax by cz p Find the minimum value of x 2 y 2 z 2 subject to the condition Click here to get an answer to your question The minimum value of x 2 y 2 z 2 if ax by cz p is Solve Study Textbooks Guides Join Login Class 12 Maths
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The following is one of the most common examples of the use of Cauchy Schwarz We can easily generalize this approach to show that if x 2 y 2 z 2 1 then the Find the maximum and minimum radii vectors of section of the surface x 2 y 2 z 2 2 a 2x 2 b 2y 2 c 2z 2 by the plane lx my nz 0
If ax by cz p then minimum value of x 2 y 2 z 2 is Doubtnut 3 39M subscribers Subscribed 29 2 9K views 5 years ago To ask Unlimited Maths Prove that minimum value of yz zx xy subject to xyz a 2 x y z is 9a 2 by Lagrange Multiplier method
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minimum value of x 2 y 2 z 2 when ax by cz p is - Find the minimum value of x y z subject to the condition ax by cz p Find the minimum value of x 2 y 2 z 2 subject to the condition