integration e x 1 sinx 1 cosx dx

integration e x 1 sinx 1 cosx dx Evaluate ex 1 sinx 1 cosx dx

Misc 24 Evaluate the definite integral 2 e 1 sin 1 cos 2 e 1 sin 1 cos 2 Evaluate the integral ex 1 sin x 1 cos x dx

integration e x 1 sinx 1 cosx dx

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integration e x 1 sinx 1 cosx dx
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Best answer The correct option b e x 2 sec x 2 Explanation Let x 2 t x 2t dx 2dt I 1 sin 2t 1 cos 2t et 2dt 2 etdt 1 sin2t 1 cos2t 2 cos2t et cost sint dt Hence the given integration is of form e x f x f x d x e x f x where f x sin x 1 cos x and f x 1 1 cos x I e x sin x 1 cos x e x sin x cos x 1

CBSE Exam class 12 About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy Safety How YouTube works Test new features NFL Sunday Ticket Symbolab is the best integral calculator solving indefinite integrals definite integrals improper integrals double integrals triple integrals multiple integrals antiderivatives and more Integration is a way to sum up parts to find the whole

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We can apply integration by parts Typically when assigning values of u and dv we want to choose a function for u that will get simpler as we differentiate it However we see that ex remain unchanged being an exponential function and sinx will alternate with cosx x as we The integrand becomes e x tan frac x 2 frac 1 2 e x sec 2 frac x 2 Since the derivative of tan frac x 2 is frac 1 2 sec 2 frac x 2 we can integrate immediately to get e x tan frac x 2 C

Answer link inte sinx cosxdx e sinx Let u sinx then du cosxdx and inte sinx cosxdx inte udu e u e sinx E sin x C You can solve the integral using a u substitution Let u sin x Differentiating we get du cos x dx Make the subtitution int e udu integrating we get e u Now back substitute for u e sin x C

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integration e x 1 sinx 1 cosx dx - Hence the given integration is of form e x f x f x d x e x f x where f x sin x 1 cos x and f x 1 1 cos x I e x sin x 1 cos x e x sin x cos x 1