integrate x 3 sin 2x dx

integrate x 3 sin 2x dx int e x cos x dx int cos 3 x sin x dx int frac 2x 1 x 5 3 int 0 pi sin x dx int a b x 2dx int 0 2 pi cos 2 theta d theta partial fractions int 0 1 frac 32 x 2 64 dx substitution int frac e x e x e x dx u e x Show More

The Integral Calculator lets you calculate integrals and antiderivatives of functions online for free Our calculator allows you to check your solutions to calculus exercises It helps you practice by showing you the full working step by step integration Enter the function you want to integrate into the editor The Integral Calculator solves an indefinite integral of a function You can also get a better visual and understanding of the function and area under the curve using our graphing tool Integration by parts formula u d v u v v d u Step 2 Click the blue arrow to submit

integrate x 3 sin 2x dx

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integrate x 3 sin 2x dx
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Integral Of Sin 2 x cos 2 x trigonometric Identities YouTube
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Solve Compute Integral New service on Mathportal You can hire our experts to do your math homework We provide complete handwritten step by step solutions Get a free quote examples example 1 x2 3x 1dx example 2 x2 sinxdx example 3 01 x2 1dx example 4 1e x lnxdx How can find the following indefinite integral x3 sin 2x dx x 3 sin 2 x d x Thanks For the Help integration Share Cite edited Nov 27 2015 at 21 04 Hosein Rahnama 14 9k 14 56 91 asked Oct 11 2015 at 11 53 zahra 11 1 4 You can try integration by parts Element118 Oct 11 2015 at 11 56

Integrate x 3 sin 2 x dx Have a question about using Wolfram Alpha Compute answers using Wolfram s breakthrough technology knowledgebase relied on by millions of students professionals For math science nutrition history geography engineering mathematics linguistics sports finance music Solution To convert this integral to integrals of the form cosjxsinxdx rewrite sin3x sin2xsinx and make the substitution sin2x 1 cos2x Thus cos2xsin3xdx cos2x 1 cos2x sinxdx Let u cosx then du sinxdx u2 1 u2 du u4 u2 du 1 5u5 1 3u3 C 1 5cos5x 1 3cos3x C

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Evaluate integral x 3 sin 2x dx by using the following reduction formulas Integration by parts is not allowed for this problem integral x m sin x dx x m cos x m integral x m 1 cos x dx integral x m cos x dx x m sin x m integralx m 1 sin x dx sin 5x sin 4x sin x sin 2x 2 sin x 1 cos 2x 2 sin x nonumber Our integral is now int 1 cos 2x 2 cos 8x sin x dx Let u cos x hence du sin x dx Making the substitution and expanding the integrand gives

Answer link Steve M Oct 26 2017 x3sin2x dx 2x4 6x 4x3 sin2x 3 6x2 cos2x 16 C Explanation We seek I x3sin2x dx In preparation for an application of integration by Parts we note that using the identity cos2A 1 2sin2A sin2x dx 1 2 1 cos2x dx 1 2 x 1 2sin2x 1 2 x 1 4sin2x How do you find the integral of x3 sin x2 dx Calculus Techniques of Integration Integration by Parts 1 Answer Sasha P Oct 11 2015 I 1 2 x2cosx2 sinx2 C Explanation x2 t 2xdx dt x3dx 1 2 x22xdx 1 2 tdt x3sinx2dx 1 2 tsintdt I u t du dt dv sintdt v sintdt cost

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integrate x 3 sin 2x dx - Try it int sin 3 2x dx int sin 2 2x sin 2x dx int 1 cos 2 2x sin 2x dx int sin 2x cos 2 2x sin 2x dx Now I should be able to integrate each of these two terms int sin 2x dx 1 2 cos 2x and int cos 2 2x sin 2x dx by letting u cos 2x we can get int cos 2 2x sin 2x dx 1 6 cos 3 2x So we get 1 2 cos