integral of x 3 sqrt 16 x 2 The answer is I 1 3sqrt 16 x 2 x 2 32 c If we make this substitution x 4sintrArrdx 4cost dt then int 64sin 3t sqrt 16 16sin 2t 4cost dt int 64sin 3t 4sqrt 1 sin 2t 4cost dt int 64sin 3t 4cost 4cost dt 64intsin 3t dt 64intsintsin 2t dt 64intsint 1
The Integral Calculator lets you calculate integrals and antiderivatives of functions online for free Our calculator allows you to check your solutions to calculus exercises It helps you practice by showing you the full working step by step integration 9 5 8K views 3 years ago Integration Integration by Substitution Integral of x 3 sqrt 16 x 2 dx more Integration by Substitution Integral of x 3 sqrt
integral of x 3 sqrt 16 x 2
integral of x 3 sqrt 16 x 2
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Integral Of 1 sqrt 16 x 2 Dx YouTube
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Free integral calculator solve indefinite definite and multiple integrals with all the steps Type in any integral to get the solution steps and graph How do you integrate x3 16 x2 by trigonometric substitution Calculus Techniques of Integration Integration by Trigonometric Substitution 3 Answers Noah G Feb 4 2017 The integral is 16 x2 3 2 3 16 16 x2 C Explanation Apply the substitution x 4sin Then dx 4cos d 4 4sin 3 16 4sin 2 cos d
How do you find the definite integral of x3 16 x2 in the interval 0 2 3 Calculus Introduction to Integration Formal Definition of the Definite Integral 3 Answers Ratnaker Mehta Jun 1 2018 40 3 Explanation Let I 2 3 0 x3 16 x2 dx We subst 16 x2 t2 x2 16 t2 2xdx 2tdt or xdx tdt 51 16K views 6 years ago Evaluate the integral using the indicated trigonometric substitution Sketch and label the associated right triangle more Evaluate the integral using the
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Conversions x 2 x msquare log msquare sqrt square nthroot msquare square le ge frac msquare msquare See Answer Question integral of x 3sqrt 16 x 2 integral of x 3 sqrt 1 6 x 2 Here s the best way to solve it Powered by Chegg AI Share Share Step 1 Let u 16 x 2 Then d u 2 x d x so 1 2 d u x d x Rewrite the integral using u and d u u 16 2 u 1 2 View the full answer Step 2 Unlock Step 3 Unlock
4 x3 81x2 16dx I started off doing u 9x to get u 93 u2 16dx which allows for the trig substitution of x asec making the denomonator 16sec2 16 tan2 1 sec2 4tan to give 4sec 9 3 4tan dx Am I doing this correctly calculus integration indefinite integrals substitution trigonometric integrals Share Cite Evaluate the Integral integral of square root of x 2 16 x 3 with respect to x x2 16 x3 dx x 2 16 x 3 d x Let x 4sec t x 4 sec t where 2 t 2 2 t 2 Then dx 4sec t tan t dt d x 4 sec t tan t d t Note that since 2 t 2 2 t 2 4sec t tan t 4 sec t tan t is positive
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integral of x 3 sqrt 16 x 2 - Ask Question Asked 5 years 11 months ago Modified 5 years 11 months ago Viewed 2k times 1 The integral is 3 1 16 x2 dx 1 3 16 x 2 d x I ve used the trig substitution method replacing x x with 4 sin 4 sin x 4 sin arcsin x 4 dx 4 cos d x 4 sin arcsin x 4 d x 4 cos d