integral of root tanx 1 tan 2x If tanx 1 tanx tan2x dx x k Atan 1 Ktanx 1 A C C is a constant of integration then the ordered pair K A is equal to A 2 1
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integral of root tanx 1 tan 2x
integral of root tanx 1 tan 2x
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So the integral of square root of tanx is equal to 1 2 tan 1 tan x 1 2 tan x 1 2 2 log tan x 1 2 tan x tan x 1 2 tan x C where C is an integration constant The first integral is immediate dt 1 t2 arctant C For the second complete the square at the denominator dt 1 t t2 dt t 1 2 2 3 4
So if I put this formula of tan 2x on the above integral then the integral will be 1 tan2x 2tan x 1 tan2x dx Now I am thinking of writing the numerator as 1 tanx 2 Substitution
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The integral calculator allows you to enter your problem and complete the integration to see the result You can also get a better visual and understanding of the function and area under the Evaluate the following integrals tanx sec2x 1 tan2x 1 t a n 2 x dx
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integral of root tanx 1 tan 2x - Explanation I 1 tan2xdx Let sin tanx so cos d sec2xdx