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int x 2 sqrt x 6 1 dx
int x 2 sqrt x 6 1 dx
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Integrate Sqrt x 2 25 X Dx This Is A Trig Substitution Video 3
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How Do You Evaluate int 4 9 frac 2 sqrt X 3
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int e x cos x dx int cos 3 x sin x dx int frac 2x 1 x 5 3 int x 2 ln 5x int frac 1 x 2 dx int frac e 2x 1 e 2x partial fractions int 0 1 frac 32 x 2 Solution Verified by Toppr x2 x6 1dx Applyu substitution ux6 u 16 udu 16 u 1 udu ApplyIntegrationByParts u u 1 v 1 u 16 2u12 u 1 uu 1du
Subtract the values frac 32 5 and 10 frac 18 5 frac 16 3 8 Add the values frac 18 5 and frac 16 3 frac 26 15 Final answer to the Let x sec u and dx sec u tan u dx so that int x 2 sqrt x 2 1 dx int sec 2 u sqrt sec 2 u 1 sec u tan u du Now simplify noting that
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Kevin Doyon 283 2 4 11 Add a comment 2 Answers Sorted by 6 We carry out the details In a comment at the end we show a somewhat simpler way Let u 1 x Hi guys This is my integral practice 22 Give it a try first and check the final answer For integral problem requests just comment down below Thank you
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int x 2 sqrt x 6 1 dx - int e x cos x dx int cos 3 x sin x dx int frac 2x 1 x 5 3 int x 2 ln 5x int frac 1 x 2 dx int frac e 2x 1 e 2x partial fractions int 0 1 frac 32 x 2