f x 1 x 2 3x 2 then f x 2

f x 1 x 2 3x 2 then f x 2 Let y x 1 We then have x y 1 Hence begin align f y f x 1 x 2 3x 2 y 1 2 3 y 1 2 y 2 2y 1 3y 3 2 y 2 5y 6 end align

Detailed Solution Download Solution PDF Concept To get the value of any function at any point with respect to some other function we need to manipulate the given Factor the original expression using ax 2 bx c a left x x 1 right left x x 2 right Substitute 2 for x 1 and frac 1 2 for x 2

f x 1 x 2 3x 2 then f x 2

3x-2y

f x 1 x 2 3x 2 then f x 2
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Let F x Be A Function Defined By F x 3x x 2x X 0 0 X
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Solve 2x 2 3x 5 0 With The Quadratic Formula YouTube
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Hence by mathematical induction f x x 2 x 3 Now that I look at this I realize that I have only shown that f n n 2 n 3 for n 0 1 2 dots It is true Free math problem solver answers your algebra homework questions with step by step explanations

Check that f x is continuous differentiable on the interval Find the values of c see below c sqrt 4 3 1 1547 The main conditions of the Mean Value Theorem Differentiation gives f f 2 3x ln x 2 1 ln x 2 1 2 3x 2 3x 2x x 2 1 3ln x 2 1 At x 1 this gives f 1 1 2 1 3ln2 So f 1 1 2 1 3ln 2

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Free Pre Algebra Algebra Trigonometry Calculus Geometry Statistics and Chemistry calculators step by step Write f x x2 3x 1 f x x 2 3 x 1 as an equation Rewrite the equation in vertex form Tap for more steps Use the vertex form y a x h 2 k y a x h 2 k to determine the

Solution and Explanation Given function is f x 1 x 2 3x 2 f x 1 x2 3x 2 This function is valid for all real values of x Solution Given function is f x 1 x2 3x 2 This function is valid for all real values of x So putting x 1 in place of x we get f x f x 1 1 f x x 1 2 3 x 1 2 f x x2

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f x 1 x 2 3x 2 then f x 2 - Let f x be denoted by y thus y 3x 2 Now interchange x and y it becomes x 3y 2 Solve for y y 2 x 3 This is f 1 x