equation of the chord of the circle x 2 y 2 4x 6y 12 0 Maths Question The equation of the chord of contact of the circle x2 y2 4x 6y 12 0 with respect to the point 2 3 is 4x 17 4x y 17 4y 17 None of these A 4x 17 B 4x y 17 C 4y 17 D None of these
MATHEMATICS Watch in App the equation of a chord of the circle x 2 y 2 4x 6y 0 is given by x 2y 0 the equation of the circle described on this chord as diameter is Socratic questions how do you find the radius of the circle x 2 y 2 4x 6y 12 0 r 5 in x 2 2 y 3 2 52 Explanation The circle equation can be arranged as x x0 2 y y0 2 r2 x2 y2 6x 6y 18 0 tiger algebra drill x 2 y 2 6x 6y 18 0
equation of the chord of the circle x 2 y 2 4x 6y 12 0
equation of the chord of the circle x 2 y 2 4x 6y 12 0
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If Y 2x Is A Chord Of The Circle X 2 Y 2 10x 0 Find The
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A Chord Of The Circle X 2 Y 2 4x 6y 0 Passing Through The
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Mathematics Question A chord of the circle x2 y2 4x 6y 0 passing through the origin subtends an angle tan 1 7 4 at the point where the circle meets positive y axis Equation of the chord is 2x 3y 0 x 2y 0 x 2y 0 2x 3y 0 A 2x 3y 0 B 2x 3y 0 C x 2y 0 D x 2y 0 Solution Verified by Toppr The radius of the circle is 5 Explanation If the equation of the circle is x2 4x y 2 6y 12 0 first of all need to complete the squares x2 4x 4 y2 6y 9 12 4 9
The equation of the chord of contact of the circle x2 y2 4x 6y 12 0 with respect to the point 2 3 is Solution Verified by Toppr Was this answer helpful 0 Similar Questions Q 1 The equation of the chord of contact of tangents drawn from the point 2 3 to the circle x2 y2 4x 6y 12 0 is View Solution Q 2 The equation of chord of the circle x2 y2 6x 4y 12 0 which passes through the origin such that origin divides it in the ratio 3 2 is A y x 0 7y 17x 0 B y 3x 0 7y 3x 0 C 4x y 0 9y 8x 0 D y 3x 7 y 3x 0
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Show That The Circle X 2 y 2 4x 6y 12 0 And X 2 y 2 6x 18y 26 0 Touch
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The Equation Of A Chord Of The Circle X 2 Y 2 3x 4y 4 0
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A Chord Of The Circle X 2 Y 2 4x 6y 0 Passing Through Origin
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Answer link Alan P Nov 1 2016 Center 3 2 XXXXX Radius 5 XXX see below for method Explanation An equation in the form XXX x a 2 y b 2 r2 is the standard form for the equation of a circle with center a b and radius r Lets try to convert the given equation XXXx2 y2 6x 4y 12 0 1 Answer George C Jan 19 2016 Rearrange into the standard form of the equation of a circle with centre 2 3 and radius 5 Explanation 0 x2 y2 4x 6y 12 x2 4x 4 y2 6y 9 25 x 2 2 y 3 2 52 Add 52 to both ends and transpose to get x 2 2 y 3 2 52 This is in the form x h 2 y k 2 r2
1 Answer Phillip E May 21 2017 The radius of the circle is 5 Explanation If the equation of the circle is x2 4x y 2 6y 12 0 first of all need to complete the squares x2 4x 4 y2 6y 9 12 4 9 This gives x 2 2 y 3 2 25 Therefore the centre of the circle is at 2 3 and the radius is 25 5 Answer link MATHS The equation of the The equation of the chord of the circle x2 y2 4x 6y 3 0 having 1 2 as it midpoint is A x y 1 0 B 2x 3y 4 0 C x y 3 0 D not existing Video Solution More from this Exercise 9 videos Text Solution Verified by Experts The correct Answer is C Share Answer
A Chord Of The Circle X 2 Y 2 4x 6y 0 Passing Through Origin
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A Chord Of The Circle X 2 Y 2 4x 6y 0 Passing Through The
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equation of the chord of the circle x 2 y 2 4x 6y 12 0 - The equation of chord of the circle x2 y2 6x 4y 12 0 which passes through the origin such that origin divides it in the ratio 3 2 is A y x 0 7y 17x 0 B y 3x 0 7y 3x 0 C 4x y 0 9y 8x 0 D y 3x 7 y 3x 0