3x 2 5x 12 03 x 2 5x 12 0 Arithmetic 699 533 Matrix 2 5 3 4 2 1 0 1 3 5 Simultaneous equation 8x 2y 46 7x 3y 47 Differentiation dxd x 5 3x2 2 Integration 01 xe x2dx Limits x 3lim
Factor by grouping Tap for more steps 3x 4 x 3 0 3 x 4 x 3 0 If any individual factor on the left side of the equation is equal to 0 0 the entire expression will The values of x that satisfy the equation are called solutions of the equation and roots or zeros of the expression on its left hand side A quadratic equation has at most two
3x 2 5x 12 03 x 2 5x 12 0
3x 2 5x 12 03 x 2 5x 12 0
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Uzupe nij Grafy 3x 1 3 x 1 5x 4 5x 3 1 5 2x 1 2x 1 0 5x 3
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If X 2 2x 3 3x 4 2x 3 3x 4 4x 5 3x 5 5x 8 10x 17
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3x2 2x 12 0 Two solutions were found x 2 148 6 1 37 3 1 694 x 2 148 6 1 37 3 2 361 Step by step solution Step 1 Equation at the end of Free math problem solver answers your algebra homework questions with step by step explanations
Step by step solution Step 1 Equation at the end of step 1 3x2 5x 12 0 Step 2 Trying to factor by splitting the middle term 2 1 Factoring 3x2 5x 12 The first term is 3x2 The equation 3x2 5x 12 0 is in the form ax2 bx c 0 with a 3 b 5 c 12 The roots are given by the quadratic formula x b b2 4ac 2a x 5
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Step by step solution Step 1 Equation at the end of step 1 3x2 5x 12 0 Step 2 Trying to factor by splitting the middle term 2 1 Factoring 3x2 5x 12 The first term is Solve 3x 2 5x 12 0 Byjus Mathsolver Byjus Solver Algebra Solution Question Solution Quadratic Formula Method 1 2 Calculate the value of the discriminant D 3 Determine
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3x 2 5x 12 03 x 2 5x 12 0 - Step by step solution Step 1 Equation at the end of step 1 3x2 5x 12 0 Step 2 Trying to factor by splitting the middle term 2 1 Factoring 3x2 5x 12 The first term is 3x2