1 x 2 is not uniformly continuous Ask Question Asked 8 years 2 months ago Modified 1 year 2 months ago Viewed 4k times 1 I need to show that 1 x2 1 x 2 is not uniformly continuous on the interval 0
0 I am trying to prove the function in the title is not uniformly continuous on 0 2 Different from the proof given in proof I proceed to show the proof following Prove that each of the following functions is not uniformly continuous on the given domain f x x 2 on mathbb R f x sin frac 1 x on 0 1 f x ln x
1 x 2 is not uniformly continuous
1 x 2 is not uniformly continuous
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Solved If f x Is Uniformly Continuous And Bounded 9to5Science
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A Continuous Function F Is Defined On The Closed Interval 4 6
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Homework Help Calculus and Beyond Homework Help Show that is not uniformly continuous on 0 Terrell Jul 25 2018 Continuous Proof verification Real 2 so 0 c 2
Solution By the definition of uniform continuity for every 0 we must find a 0 such that for all x y in the domain if x y then f x f y We show that fis not uniformly continuous on S i e 9 0 8 0 9x 0 2S9x2S jx x 0j and 1 x 1 x 0 Let 1 Choose 0 Let x 0 min 1 and x x 0 2 Then jx x 0j x 0 2 2
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F x sin 1 x from Example 2 is NOT uniformly continuous on 0 1 because fhas no continuous extension on a b Proof The proof is magical We ll do some wishful thinking Try to prove it Example 1 The function f x 1 1 x2 is uniformly continuous on R Proof Note that for any x u 2 R jf x 1 f u j x2 jx uj jx 1 u2 1 x2 1 u2
f x f y Alternatively you can elementarily show that f is Lipschitz on mu infty for mu 0 using the fact that lvert 1 x 1 y rvert lvert x y rvert xy 2 and xy mu 2 To show
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Solved The Second Example Shows That non uniform Chegg
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1 x 2 is not uniformly continuous - A function f x is not uniformly continuous on D if there is some 0 such that for every 0 no matter how small it is possible to nd x y 2D with jx yj but jf x f y j For